Bubble sort is a simple sorting algorithm that works by repeatedly stepping
through the list to be sorted, comparing each pair of adjacent items and
swapping them if they are in the wrong order. The pass through the list is
repeated until no swaps are needed, which indicates that the list is
sorted. The algorithm gets its name from the way smaller elements "bubble"
to the top of the list. Because it only uses comparisons to operate on
elements, it is a comparison sort. Although the algorithm is simple, most
of the other sorting algorithms are more efficient for large lists. Bubble
sort is not a stable sort which means that if two same elements are
there in the list, they may not get their same order with respect to
each other.
Third Pass:
( 1 2 4 5 8 ) ( 1 2 4 5 8 )
( 1 2 4 5 8 ) ( 1 2 4 5 8 )
( 1 2 4 5 8 ) ( 1 2 4 5 8 )
( 1 2 4 5 8 ) ( 1 2 4 5 8 )
through the list to be sorted, comparing each pair of adjacent items and
swapping them if they are in the wrong order. The pass through the list is
repeated until no swaps are needed, which indicates that the list is
sorted. The algorithm gets its name from the way smaller elements "bubble"
to the top of the list. Because it only uses comparisons to operate on
elements, it is a comparison sort. Although the algorithm is simple, most
of the other sorting algorithms are more efficient for large lists. Bubble
sort is not a stable sort which means that if two same elements are
there in the list, they may not get their same order with respect to
each other.
Step-by-step example
Let us take the array of numbers "5 1 4 2 8", and sort the array from lowest
number to greatest number using bubble sort. In each step, elements
written in bold are being compared. Three passes will be required.
number to greatest number using bubble sort. In each step, elements
written in bold are being compared. Three passes will be required.
First Pass:
( 5 1 4 2 8 ) ( 1 5 4 2 8 ), Here, algorithm compares the first two
elements, and swaps since 5 > 1.
( 1 5 4 2 8 ) ( 1 4 5 2 8 ), Swap since 5 > 4
( 1 4 5 2 8 ) ( 1 4 2 5 8 ), Swap since 5 > 2
( 1 4 2 5 8 ) ( 1 4 2 5 8 ), Now, since these elements are already in
order (8 > 5), algorithm does not swap them.
( 5 1 4 2 8 ) ( 1 5 4 2 8 ), Here, algorithm compares the first two
elements, and swaps since 5 > 1.
( 1 5 4 2 8 ) ( 1 4 5 2 8 ), Swap since 5 > 4
( 1 4 5 2 8 ) ( 1 4 2 5 8 ), Swap since 5 > 2
( 1 4 2 5 8 ) ( 1 4 2 5 8 ), Now, since these elements are already in
order (8 > 5), algorithm does not swap them.
Second Pass:
( 1 4 2 5 8 ) ( 1 4 2 5 8 )
( 1 4 2 5 8 ) ( 1 2 4 5 8 ), Swap since 4 > 2
( 1 2 4 5 8 ) ( 1 2 4 5 8 )
( 1 2 4 5 8 ) ( 1 2 4 5 8 )
Now, the array is already sorted, but our algorithm does not know if it is
completed. The algorithm needs one whole pass without any swap to
know it is sorted.
( 1 4 2 5 8 ) ( 1 4 2 5 8 )
( 1 4 2 5 8 ) ( 1 2 4 5 8 ), Swap since 4 > 2
( 1 2 4 5 8 ) ( 1 2 4 5 8 )
( 1 2 4 5 8 ) ( 1 2 4 5 8 )
Now, the array is already sorted, but our algorithm does not know if it is
completed. The algorithm needs one whole pass without any swap to
know it is sorted.
Third Pass:
( 1 2 4 5 8 ) ( 1 2 4 5 8 )
( 1 2 4 5 8 ) ( 1 2 4 5 8 )
( 1 2 4 5 8 ) ( 1 2 4 5 8 )
( 1 2 4 5 8 ) ( 1 2 4 5 8 )
Algorithm
Step 2: Set j=1
Step 3: Repeat while j<=n
(A) if a[i] < a[j]
Then interchange a[i] and a[j]
[End of if]
(B) Set j = j+1
[End of Inner Loop]
[End of Step 1 Outer Loop]
Step 4: Exit
Optimized Pseudo-code
procedure bubbleSort( A : list of sortable items )
n = length(A)
repeat
swapped = false
for i = 1 to n-1 inclusive do
if A[i-1] > A[i] then
swap(A[i-1], A[i])
swapped = true
end if
end for
n = n - 1
until not swapped
end procedure
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